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IGCSE Physics 0625 Paper 4 Theory Extended Solved Jun 2025

CAMBRIDGE IGCSE™ PHYSICS 0625/43
May/June 2025 – Paper 4 Theory (Extended)
ANSWER-FILLED VERSION

 

Maximum mark: 80 | Time: 1 hour 15 minutes

Answers and working are based on the June 2025 (v3) Question Paper and Mark Scheme.

Question 1 – Motion [7 marks]

Part

Answer / Working

Marks

1(a)

11.5 m s⁻¹ 1

1(b)

Distance = area under graph = ½(0.5)(20) + ½(3.5)(20) = 45 m.

3

1(c) Deceleration = Δv/Δt = 20/(4.0−0.5) = 5.7 m s⁻².

3

 

Question 2 – Momentum and Forces [6 marks]

Part

Answer / Working

Marks

2(a)

p = mv (momentum = mass × velocity).

1

2(b)

Conservation of momentum: 720v + (120×7850) = 6.55×10⁶; v = (6.55×10⁶−9.42×10⁵)/720 = 7.79×10³ m s⁻¹ = 7790 m s⁻¹.

3

2(c)

At terminal velocity, weight = upward force = 120000 N. m = W/g = 120000/9.8 ≈ 12000 kg.

2

 

Question 3 – Work, Energy and Power [7 marks]

Part

Answer / Working

Marks

3(a)

W = Fd, so F = 110/0.45 = 244 N ≈ 240 N. 2

3(b)(i)

110 = ½(0.030)v²; v = √(220/0.030) ≈ 86 m s⁻¹.

3

3(b)(ii) Air resistance/drag/friction acts; energy is transferred to the surroundings (thermal energy), so speed decreases.

2

 

Question 4 – Thermal Physics [8 marks]

Part

Answer / Working

Marks

4(a)

Copper contains free/delocalised electrons. They carry thermal energy and collide with ions; lattice vibrations also transfer energy to neighbouring ions. 3

4(b)(i)

Thermal energy transferred per unit mass per unit temperature change.

2

4(b)(ii) Water gains: 50×4.2×9 = 1890 J. Metal loses: 54×c×69. Equate: 54c×69=1890, so c=0.51 J g⁻¹ °C⁻¹.

3

 

Question 5 – Refraction [7 marks]

Part

Answer / Working

Marks

5(a)

Ratio of the speed of light in air to its speed in water; equivalently sin i/sin r.

1

5(b)

P continues vertically. Q refracts away from the normal in the correct direction.

2

5(c)

n = 1/sin49° ≈ 1.3.

2

5(d)

Light travels from denser water to less dense air and the incidence angle is greater than the critical angle (49°), so total internal reflection occurs.

2

 

Question 6 – Ultrasound [6 marks]

Part Answer / Working

Marks

6(a)

Sound with frequency higher than 20 kHz.

1

6(b)

Particle vibrations are parallel to the direction of propagation.

1

6(c)(i)

Send an ultrasound pulse into water; it reflects from the object; measure the time to travel to the object and back; use the speed/time relationship to determine depth (including the factor ½ for the return journey).

3

6(c)(ii)

Medical scanning of soft tissue. (Non-destructive testing is also accepted.)

1

 

Question 7 – Electric Circuits [7 marks]

Part

Answer / Working

Marks

7(a)

0.50 A

1

7(b)

V = IR = 0.50×6.0 = 3.0 V.

2

7(c)

12−3.0 = 9.0 V.

1

7(d)

I₂=9.0/20=0.45 A; I₁=0.50−0.45=0.05 A; R=9.0/0.05=180 Ω.

3

 

Question 8 – Electric Fields and Charge [8 marks]

Part Answer / Working

Marks

8(a)(i)

A region where an electric charge experiences a force.

1

8(a)(ii)

Four straight radial field lines directed inward toward the negative point charge.

2

8(b)

Q=W/V. 4.5×10⁵ MJ = 4.5×10¹¹ J. Q=(4.5×10¹¹)/(2.9×10⁸)≈1.6×10³ C = 1600 C.

3

8(c)

Q=It=2.0×120=240 C.

2

 

Question 9 – Transformers [9 marks]

Part Answer / Working

Marks

9(a)(i)

AC in primary produces a changing magnetic field; soft-iron core transfers it to the secondary; changing field links/cuts the secondary, inducing an e.m.f. and alternating current.

3

9(a)(ii)

Vs/Vp=Ns/Np=20/1; Vs=12×20=240 V. 2

9(b)

P=I²R; I²=(1.25×10⁻³)/0.050=0.025; I=√0.025=0.16 A.

2

9(c) Less power/heating/energy loss; thinner/cheaper cables. (Fewer pylons or longer-distance transfer are also accepted.)

2

 

Question 10 – Space Physics [8 marks]

Part Answer / Working

Marks

10(a)

Distance travelled in the vacuum of space by light in one year.

1

10(b)

d=ct=3.0×10⁸×490=1.47×10¹¹ m≈1.5×10¹¹ m.

2

10(c) H₀=gradient=v/d. Using the best-fit line: (2.5×10⁴)/(100×10²⁰)=2.5×10⁻¹⁸ s⁻¹.

3

10(d)

Redshift is an observed increase in wavelength of electromagnetic radiation/light from distant galaxies compared with the wavelength measured on Earth.

2

 

Question 11 – Nuclear Physics [7 marks]

Part

Answer / Working

Marks

11(a)

Time taken for half the nuclei in any sample of a radioactive isotope to decay. 1

11(b)(i)

²³⁴₉₁Pa → ²³⁴₉₂U + ⁰₋₁β⁻ 3
11(b)(ii) A neutron changes into a proton (plus an electron).

1

11(c) α-particles have greater kinetic energy than β-particles; α-particles also have greater electric charge than β-particles.

2

 

Accuracy / format note: For drawing questions (5(b) and 8(a)(ii)), the required diagram content is stated explicitly in words.

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